Executing Bash Script by help of cron scheduler

[syed]

Dear salam to all

I want to excute the following script with help of cron scheduler every morning at 9.00 am. Can any body help me?


#!/bin/bash

LOG=/tmp/mylog.log
SECONDS=10
EMAIL=my@email.address

for i in $@; do
echo "$i-UP!" > $i.$LOG
done

while true; do
for i in $@; do
ping -c 1 $i &> /dev/null
if [ $? -ne 0 ]; then
STATUS=`cat $i.$LOG`
if [ $STATUS != "$i-DOWN!" ]; then
echo "`date`: ping failed, $i host is down!" |
mail -s "$i host is down!" $EMAIL
fi
echo "$i-DOWN!" > $i.$LOG
else
STATUS=`cat $i.$LOG`
if [ $STATUS != "$i-UP!" ]; then
echo "`date`: ping OK, $i host is up!" |
mail -s "$i host is up!" $EMAIL
fi
echo "$i-UP!" > $i.$LOG
fi
done
sleep $SECONDS
done


Regards,

SM Raza

[mudasir]

Its simple.

run this command "crontab -e" then make an entry similar to given below

* 9 * * * /path/to/script

then save and exit. make sure the script has executable rights.

[lambda]

that will execute 60 times, once a minute from 9:00 to 9:59.

0 9 * * * is what you want.

it doesn't seem like the script will ever exit. perhaps cron is not the place for it.

[syed]

Salam 2 all

thanks for reply. Then where should it be placed.



Regards


Raza

[lambda]

remove the outer while loop so that it does exit after a 10 seconds.

install runit or daemontools (probably part of your distribution), and run it using that.

[ranatanveer]

AOA SM Raza

one suggestion:

what if mail delivered in case of only host down ?

and you can configure mail-to-sms from any service provider in pakistan so that you get mail at ur mobile as SMS.